CDF

Interface

CDF

This function evaluates the CDF of the Bradford distribution with given argument, defined by

and

where

In the following figure a =-10 b= 10 and the curve of the line is set by c =5

Example 1

In the example that follows, the CDF is evaluated using values from 0 up to 0.8 with a step equal to 0.1. The maximum number of precision digits, implicitly set to 17, may be changed through the <em> PRECISION </em> define.

#include <codecogs/stats/dists/continuous/bradford/cdf.h>
#include <iostream>
#include <iomanip>
 
#define PRECISION 17
 
int main()
{
  std::cout << "The values of the Bradford CDF with " << std::endl;
  std::cout << "a = 0, b = 0.7, c = 3 and" << std::endl;
  std::cout << "x = {0, 0.1, 0.2, ... , 0.8} are" << std::endl;
  std::cout << std::endl;
  std::cout << std::setprecision(10);
  for (double x = 0; x < 0.81; x += 0.1)
  {
    std::cout << std::setprecision(1);
    std::cout << "x = " << std::setw(3) << x << " : ";
    std::cout << std::setprecision(PRECISION);
    std::cout << Stats::Dists::Continuous::Bradford::CDF(x, 0, 0.7, 3);
    std::cout << std::endl;
  }
  return 0;
}

Output

The values of the Bradford CDF with
a = 0, b = 0.7, c = 3 and
x = {0, 0.1, 0.2, ... , 0.8} are
 
x =   0 : 0
x = 0.1 : 0.25728658641487911
x = 0.2 : 0.44654239804174406
x = 0.3 : 0.59632253897119802
x = 0.4 : 0.72028629569299074
x = 0.5 : 0.82603834828984657
x = 0.6 : 0.91825063385856021
x = 0.7 : 1
x = 0.8 : 1

References

John Burkardt's library of statistical C++ routines, http://www.csit.fsu.edu/~burkardt/cpp_src/prob/prob.html

Parameters

x	the argument of the CDF
a	the first parameter of the distribution (strictly less than b)
b	the second parameter of the distribution
c	the third parameter of the distribution (strictly positive)

Returns

the CDF of the Bradford distribution

Authors

Lucian Bentea (September 2005)

Source Code

Source code is available when you agree to a GP Licence or buy a Commercial Licence.

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