Interface
#include <codecogs/maths/combinatorics/permutations/permutationlex.h>
using namespace Maths::Combinatorics::Permutations;
| class | PermutationLex
Progressively generates all the permutations of the given size, in lexicographic order. | [constructor] | PermutationLex (int n) constructor that initializes the class to generate permutations of size n | | std::vector<int> getNext | unknown () generates the next permutation in lexicographic order; if all have been considered, it starts again from the first | | int | getRank () returns the rank of the current permutation | | int | m_n | | std::vector<int> m_p | unknown | | bool | m_even | | void | init () |
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Class PermutationLex
Consider the permutations of size
n
and
Now consider the next two numbers in the numerical base

, corresponding to each permutation
Then

is said to be the lexicographic succesor of

if and only if

.
This class progressively generates all the permutations of the given size, in lexicographic order, starting with the identical permutation.
Example:
#include <codecogs/maths/combinatorics/permutations/permutationlex.h>
#include <iostream>
int main()
{
Maths::Combinatorics::Permutations::PermutationLex P(7);
std::cout << "The first 5 lexicographic permutations of 7 elements:";
std::cout << std::endl;
for (int i = 0; i < 5; i++)
{
std::vector<int> alpha = P.getNext();
for (int j = 0; j < alpha.size(); j++)
std::cout << alpha[j] << " ";
std::cout << "\t rank = " << P.getRank();
std::cout << std::endl;
}
return 0;
}Output:
The first 5 lexicographic permutations of 7 elements:
1 2 3 4 5 6 7 rank = 1
1 2 3 4 5 7 6 rank = 2
1 2 3 4 6 5 7 rank = 3
1 2 3 4 6 7 5 rank = 4
1 2 3 4 7 5 6 rank = 5
References:
SUBSET, a C++ library of combinatorial routines, http://www.csit.fsu.edu/~burkardt/cpp_src/subset/subset.html
Authors
- Lucian Bentea (August 2005)
Source Code
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